intersection_update

Description

Updates the set, keeping only elements found in it and all others.

Syntax

set. intersection_update(iterable, …)

iterable, …

Required. Iterable or multiple iterables to be compared against the set.

Return Value

None

Time Complexity

#TODO

Example

>>> s = {1, 2}
>>> s.intersection_update([2, 3])
>>> s
set([2])
>>> s = {1, 2}
>>> s.intersection_update([0, 1], [1, 2])
>>> s
set([1])

See also

#TODO