count

Description

Returns the number of non-overlapping occurrences of a substring in the searched string.

Syntax

str. count(sub[, start[, end]])

sub

Required. The string searched for.

start

Optional. Index from which to start counting. Default is 0 (start of the string).

end

Optional. The end index for the search. End of the string is the default value.

Return Value

int

Time Complexity

#TODO

Remarks

Optional arguments start and end are interpreted as in slice notation.

Example

>>> "ABCAB".count("A")
2
>>> "ABCAB".count("A", 1)
1
>>> "ABCAB".count("A", 1, 2)
0
>>> "ABCAB".count("D", 1, 2)
0

See Also

#TODO